Question

How to get existing control s ControlTemplate in WPF in XAML format (visual tree)? This is to help to create new ControlTemplate with the help of existing template.

Answer 1

。

但是,你也可以扩大现有的风格,而不通过使用<<>基于<><>>>的属性重新界定一切。

Answer 2

查阅

它将排除用于控制中建筑的标准风格(因此模板也是如此)。你们还可以装上包含WPF控制的具体DL,并对那些人的缺省风格进行观察。

Answer 3

如果您有 Expression Blend 你可以:

Drag the control onto the design surface
Right click the control and choose Edit Template -> Edit Copy

当你这样做时,Blend将从控制中抽取基础模板,并在文件/申请中明确宣布该模板是你可以用来支持你的灵魂的资源。你们可以做任何控制。

Answer 4

由Matthew MacDonald撰写的《2008年C#》一书载有第15章中的“控制模板浏览器”。我认为,你可以简单地从Apress网站下载样本代码。

Answer 5

<2020 Update:

All the styles and templates of WPF components are now moved here.
But, before creating a new component, just check this to see if you have a good alternative to that (maybe changing the style can work).
Note: Usually, it has a bunch of DynamicResource bindings that you might want to replace with yours and make static. If you don t want to do much manual work, you might consider using the second solution below.

第二种和较短的解决办法可能使用Microsoft Blend至extract 。该模板包括以下步骤:

Right-click on the control > Edit Template>Edit Current OR Edit a pidt a

But be careful with this one, as it doesn t always export the whole template,
but the necessary part of it.
Just consider comparing this template with the official one (mentioned above) to make sure everything is fine.

Answer 6

http://www.sellsbrothers.com/tools/#ShowMeTheTemplate”rel=“nofollow noreferer” 缩略语

Answer 7

Use Microsoft Blend for it: Paste your entire XAML code in a file in this tool and right click the control whose visual tree you want to perceive:

Select the option: Edit template and there you go

Answer 8

The XamlWriter class provides you with this functionality. If controlName is the Name of a Control then using the below snippet you get the Xaml of the Control s Template inside the stringBuilder object. I guess tools mentioned in the answers utilize this class.

var stringBuilder = new StringBuilder();
var xmlSettings = new XmlWriterSettings
{
  Indent = true
};

using (var xmlWriter = XmlWriter.Create(stringBuilder, xmlSettings))
{
  XamlWriter.Save(controlName.Template, xmlWriter);
}

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