鉴于酒类中的XML成分类似:
$( <foo oy="vey" foo="bar" here="is" another="attribute" /> )
我是否能够利用 j或老大Script,获得含有XML要素所有特性名称的阵列? 我期望:
[ oy , foo , here , another ]
鉴于酒类中的XML成分类似:
$( <foo oy="vey" foo="bar" here="is" another="attribute" /> )
我是否能够利用 j或老大Script,获得含有XML要素所有特性名称的阵列? 我期望:
[ oy , foo , here , another ]
j 彩票功能是真的指使XML的,它可以穿透超文本,但并不真实。
如何使用浏览器XML教区:
function parseXML(text) {
var parser, xmlDoc;
if (window.DOMParser) {
parser = new DOMParser();
xmlDoc = parser.parseFromString(text,"text/xml");
} else { // IE
xmlDoc= new ActiveXObject("Microsoft.XMLDOM");
xmlDoc.async = "false";
xmlDoc.loadXML(text);
}
return xmlDoc;
}
// Demo
var doc = parseXML( <foo oy="vey" foo="bar" here="is" another="attribute" /> );
var foo = doc.childNodes[0];
for (var i = 0; i < foo.attributes.length; i++) {
var attr = foo.attributes[i];
alert(attr.name + " = " + attr.value);
}
http://jsbin.com/ezawe“rel=“noretinger”>here。
http://plugins.jquery.com/project/getAttributes”rel=“nofollow noreferer”> 这一金字节将有助于你做到这一点。
你们也可以使用老旧的 j子,如:
var elt = document.getElementsByTagName( id );
for (i=0;i<elt.attributes.length;i++){
//elt.attributes[i].nodeName is what you want, .nodeValue for its value.
}
<Foo>
elementDo you need list of attributes of a single element?
... if so - do you really need an array?
Simple $( <foo ... /> ).get(0).attributes
...will give you NamedNodeMap (object) of attributes
<Foo>
in the whole (XML) document@Soufiane Hassou s answer is showing approach but is missing the inner loop...
您是否需要在一份<全程>的XML文件中找到所有可能的内容(例如产品内容)的名称?
var yourElements = document.getElementsByTagName( Foo ); //get all <Foo> elements
var listOfAttributeNames = []; //prepare empty array for attribute names
var attributeNameBuffer; //buffer for current attribute name in loop
//Loop all elements
for(var i = 0; i < yourElements.length ; ++i){
//Loop all attributes of a current element
for( k = 0 ; k < yourElements[i].attributes.length ; ++k ){
//Temporary store current attribute name
attributeNameBuffer = yourElements[i].attributes[k].name;
//First,
//test if the attribute name does not already exist in our array of names
if( listOfAttributeNames.indexOf(attributeNameBuffer) == -1 )
listOfAttributeNames.push( attributeNameBuffer ); //if not, add it
}
}
console.log(listOfAttributeNames); //display array of attributes in console