Question

How could I find directories with the name of specific length? For example, I have bunch of directories which have length of the name equal to 33 chars ( a92e8cc611fdebcca3cf2fc8dc02c918 , c442fb3f46d6c8bd17d27245290a9512 and so on). Does find utility accepts condition in form of the wc -c ? Or maybe some other utilities should be piped together?

Answer 1

与全球团结联盟接触的途径很少

$ find . -type d -name "?????????????????????????????????"

$ find /path -type d -printf "%f
" | awk  length==33

Answer 2

你没有 Java子,但如果你写了档案,以概括你所铭记的任何标准,将其带上 j子。如果你想tra倒整个目录结构,你就不得不回响,但完全是可行的。

职业介绍,它只是描述的。

阿帕奇共同组织JAR拥有一些可以轻松地从事这项工作的冰箱和目录。

Answer 3

保证:

find dir -name  ?????????????????????????????????

(33小时<代码>?)。

Answer 4

find . -type d -exec bash -c  x=`basename {}`; [[ ${#x} == 33 ]] &&  echo $x   ;

这可能因为你拥有的档案数量而缓慢。

To clarify: ${#x} -> finds the length of a string and basename -> finds the name of the final directory

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