Question

我试图从Javagust Regex的档案中提取一个子。这里是档案中的一个切片:

DATE:20091201T220000
SUMMARY:Dad s birthday

我想提取的田地是“摘要”。这里的做法是:

extractSummary : function(iCalContent) {
  /*
  input : iCal file content
  return : Event summary
  */
  var arr = iCalContent.match(/^SUMMARY:(.)*$/g);
  return(arr);
}

Answer 1

https://developer.mozilla.org/en-US/docs/Web/Java/Reference/Global_Objects/RegExp#Syntax”rel=“noreferer”

multiline; treat beginning and end characters (^ and $) as working over multiple lines (i.e., match the beginning or end of each line (delimited by or ), not only the very beginning or end of the whole input string)

还将<代码>*放在正确位置:

"DATE:20091201T220000
SUMMARY:Dad s birthday".match(/^SUMMARY:(.*)$/gm);
//------------------------------------------------------------------^    ^
//-----------------------------------------------------------------------|

Answer 2

function extractSummary(iCalContent) {
  var rx = /
SUMMARY:(.*)
/g;
  var arr = rx.exec(iCalContent);
  return arr[1]; 
}

你们需要这些变化:

Put the * inside the parenthesis as suggested above. Otherwise your matching group will contain only one character.
查阅<代码><>>>和<代码><>。随着全球选择的到来,它们与全面扼制的开始和结束,而不是线的开始和结束。相反,在明确的新路线上搭桥。
I suppose you want the matching group (what s inside the parenthesis) rather than the full array? arr[0] is the full match (" SUMMARY:...") and the next indexes contain the group matches.
String.match(regexp) is supposed to return an array with the matches. In my browser it doesn t (Safari on Mac returns only the full match, not the groups), but Regexp.exec(string) works.

Answer 3

您的定期表达很可能是想的。

/
SUMMARY:(.*)$/g

我想要使用的一个小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小小,就是与阵列相配。

var arr = iCalContent.match(/
SUMMARY:(.*)$/g) || [""]; //could also use null for empty value
return arr[0];

这样,当你使用<代码>arr<>/code>时,你不会发现任何类型的错误。

Answer 4

该法典规定:

let str = "governance[string_i_want]"; 
let res = str.match(/[^governance[](.*)[^]]/g);
console.log(res);

仇恨将等于“扼杀_i_want”。然而,在这种例子中,树脂仍是一个阵容,因此不像一种扼杀。

守则将我不希望的特性分类,使用[说明],对方括号之间的内容加以匹配,从而摘取我想要的描述!

您可以在此尝试:。 https://www.w3schools.com/jsref/tryit.asp?filename=tryjsref_match_regexp 。

Good luck.

Answer 5

<代码>(*>,代替(>)*。后者将只反映最后一行。

此外,无需逃避<代码>:。

Answer 6

你们应当利用:

var arr = iCalContent.match(/^SUMMARY:(.)*$/g);
return(arr[0]);

Answer 7

这是你如何用javascript将iCal档案整理成文。

    function calParse(str) {

        function parse() {
            var obj = {};
            while(str.length) {
                var p = str.shift().split(":");
                var k = p.shift(), p = p.join();
                switch(k) {
                    case "BEGIN":
                        obj[p] = parse();
                        break;
                    case "END":
                        return obj;
                    default:
                        obj[k] = p;
                }
            }
            return obj;
        }
        str = str.replace(/
 /g, " ").split("
");
        return parse().VCALENDAR;
    }

    example = 
     BEGIN:VCALENDAR
 +
     VERSION:2.0
 +
     PRODID:-//hacksw/handcal//NONSGML v1.0//EN
 +
     BEGIN:VEVENT
 +
     DTSTART:19970714T170000Z
 +
     DTEND:19970715T035959Z
 +
     SUMMARY:Bastille Day Party
 +
     END:VEVENT
 +
     END:VCALENDAR
 


    cal = calParse(example);
    alert(cal.VEVENT.SUMMARY);

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