Question

我试图将桌面应用程序连接起来,我是同D.icio.us api @ Delicious API/a,简单地向他们提供我的用户名和密码,并请他们把书记上张贴在我的简介上。

我面临的问题是,我不理解在我开放联系时如何派我的 log。

我怎么做呢?

Answer 1

查阅网站:

所有文件/文件都需要https request和HTTP-Auth。

HTTP-Auth is header used in basic authentication.
In Java, you can simply put your credentials in the URL:

http://user:pass@www.example.com/

您可以核实,该编码是使用)方法正确确定的。

Answer 2

HttpUrlConnection允许你履行 http://blog.taragana.com/index.php/archive/java-tip-basic-authentication-with-httpurllinkion/"rel=“nofollow noretinger”>basic accreditation 。较强大的HttpClient libraru为你提供了 more Solutions(Basic, Digest, and NTLM- 我认为需要)。

Answer 3

如果你确实需要吉大港山区基本居住条件,你可以像现在这样形成:

http://user:password@www.website.com

最新资料:

利用所提供的实例,这项工作应当:

https://user:password@api.del.icio.us/v1/posts/add&url=http://www.google.com&description=awesome

Answer 4

HttpURLConnection确实允许你做基本的 au,但如果你希望更复杂的认证能够工作,请Apache HTTPClient 。它可以无缝地通过http://www.un.org/www.un.org/french/ga/president

http://hc.apache.org/http://client-3.x/authentication.html>rel=“nofollow noreferer”>HTTPClient Authentication Guide

Answer 5

答案是:

public String reloadTomcatWebApplication(String user, String pwd, String urlWithParameters, boolean returnResponse){        
    URL url = null;
    try {

        url = new URL(urlWithParameters);
    } catch (MalformedURLException e) {
        System.out.println("MalformedUrlException: " + e.getMessage());
        e.printStackTrace();
        return "-1";
    }

    URLConnection uc = null;
    try {
        uc = url.openConnection();
    } catch (IOException e) {
        System.out.println("IOException: " + e.getMessage());
        e.printStackTrace(); 
        return "-12";
    }


    String userpass = user + ":" + pwd;
    String basicAuth = "Basic " + javax.xml.bind.DatatypeConverter.printBase64Binary(userpass.getBytes());

    uc.setRequestProperty ("Authorization", basicAuth);

    InputStream is = null;
    try {
        is = uc.getInputStream();
    } catch (IOException e) {
        System.out.println("IOException: " + e.getMessage());
        e.printStackTrace();
        return "-13";
    }
    if(returnResponse){
    BufferedReader buffReader = new BufferedReader(new InputStreamReader(is));
    StringBuffer response = new StringBuffer();

    String line = null;
    try {
        line = buffReader.readLine();
    } catch (IOException e) {
        e.printStackTrace();
        return "-1";
    }

    while (line != null) {
        response.append(line);
        response.append( 
 );
        try {
            line = buffReader.readLine();
        } catch (IOException e) {
            System.out.println(" IOException: " + e.getMessage());
            e.printStackTrace();
            return "-14";
        }
    }

    try {
        buffReader.close();
    } catch (IOException e) {
        e.printStackTrace();
        return "-15";
    }       
    System.out.println("Response: " + response.toString());
    return response.toString();

    }               
    return "0";
}

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