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complex batch replacement linux
原标题:

I m trying to do some batch replacement for/with a fairly complex pattern

So far I find the pattern as:

find  (  -name  *.php  -o -name  *.html   )  -exec grep -i -n  hello  {} +

The string I want to replace is currently as follow:

<img src="/some/path/to/somewhere/hello" /> 

where the path for the image varies but always contain the sub-string hello at the end

I would like to grab the path and perform a replacement as follow:

<img src="<?php myfunction( (/some/path/to/somewhere/) ); ?>" /> 

What would a good way to perform this?

Any help will be appreciate it.

最佳回答

Replace -exec grep ..... with

-exec cat  {}  | sed s/<img src="(/some/path/to/somewhere/)hello" />/<img src="<?php myfunction( (1)(constant) ); ?>" />/ > /tmp/output; mv /tmp/output  {}   ; 

escaping spaces, " and / symbols in sed s search and replacement patterns with backslahes as sed likes.

For instance, this will extract /path/:

echo "<img src="/path/hello"" | sed "s/<img src="(/path/)hello/1/"
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