Question

PHP + javascript code + flv player:

I am trying to play a .flv video on a web page and I have the file name to play from mysql database so i need to use PHP. In the code below there is a script that runs a video player (favideo from Adobe).

This video player work fine when the web page have the .html extension and it won t work with .php one, resulting my php code not working.

thanks in advance.

here is the code:

    <HTML>
<head>
<title> PropertyVideo
</title>
    <script src="AC_RunActiveContent.js" type="text/javascript"></script>
    <script src="FAVideo.js" type="text/javascript"></script>
</head>
<body onLoad="">
<?php
    include  ../Header.php ;
    require  ../../DataLayer/property_video.php ;
    //$id=$_GET[ pro_id ];
    $id=1;
    $vid=new property_video();
    $vids=$vid->GetRecords("property_id=".$id);
    $vid=$vids[0];
    $path = $vid->path;
?>
<div id="divOne"></div>
    <script type="text/javascript">
        playerOne = new FAVideo("divOne", <?PHP echo $path ?>,0,0,{ autoLoad:true, autoPlay:true });
    </script>
    <script>
        playerOne.addEventListener("playheadUpdate",this,myHandler);

        playerOne.removeEventListener("playheadUpdate",this,myHandler);

        function myHandler() 
        {
            //alert("eh");
        }
    </script>

<?php
    include  footer.php ;
?>
</body>
</HTML>

and the actual generated html code is:

<HTML>

PropertyVideo WelCome6 playerOne = new FAVideo("divOne", demo_video.flv,0,0,{ autoLoad:true, autoPlay:true });

<script>
    playerOne.addEventListener("playheadUpdate",this,myHandler);

    playerOne.removeEventListener("playheadUpdate",this,myHandler);

    function myHandler() 
    {
        //alert("eh");
    }
</script>

Answer 1

There might be more errors, but you certainly need to add some quotes to the path:

playerOne = new FAVideo("divOne", "<?PHP echo $path ?>",0,0,{ autoLoad:true, autoPlay:true });

Answer 2

You have some JavaScript that works.

You have some PHP that generates some JavaScript that doesn t work.

Therefore, the JavaScript you are generating doesn t match the JavaScript you know works.

Throwing some PHP down and saying "This doesn t work" is not a good approach to solving the problem.

You should be comparing the output of the PHP with the JavaScript that you know works.

(I d guess it probably has something to do with missing quote marks around a JS string)

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