Question

I need to find word count for all of the files within a folder.

Here is the code I ve come up with so far:

$f="../mts/sites/default/files/test.doc";

// count words
$numWords = str_word_count($str)/11;
echo "This file have ". $numWords . " words";

This will count the words within a single file, how would I go about counting the words for all files within a given folder?

Answer 1

how about

$array = array(  file1.txt ,  file2.txt ,  file3.txt  );
$result = array();
foreach($array as $f ){
 $result[$f] = str_word_count(file_get_contents($f));
}

and using the dir

if ($handle = opendir( /path/to/files )) {
    $result = array();
    echo "Directory handle: $handle
";
    echo "Files:
";

    /* This is the correct way to loop over the directory. */
    while (false !== ($file = readdir($handle))) {
       if($file ==  .  || $file ==  .. )
           continue;
       $result[$file] = str_word_count(file_get_contents( /path/to/files/  . $file)); 
       echo "This file {$file} have {$result[$file]} words";
    }

    closedir($handle);
}

Lavanya, you can consult the manual of readdir, file_get_contents.

Answer 2

Assuming the doc files are plaintext and don t contain additional markup, you can use the following script to count all of the words in all of the files:

<?php
$dirname =  /path/to/file/ ;
$files = glob($dirname. * );
$total = 0;
foreach($files as $path) {
    $count = str_word_count(file_get_contents($path));
    print "
$path has $count words
";
    $total += $count;
}
print "Total words: $total

";
?>

Answer 3

If you are using *nux than you can use system( cat /tmp/* | wc -w )

Answer 4

You can use $words = str_word_count(file_get_contents($filepath)) to get the word count of a text file, however this won t work for word docs. You ll need to find a library or external program that can read the .doc file format.

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