Question

I have a piece of codes that resizes a .png file in php. It start with:

$im = new Imagick( "strawberry.png" );

I have a .png file in www.mydomain.com eststrawberry.png. How can I correct the code above for this address?

Thanks

Answer 1

Try to figure out the path from where your script runs. From there, you can use a relative path to the test directory.

E.g.

If your script is located in the root directory for the www.mydomain.com site, then you can use this:

$im = new Imagick("./test/strawberry.png");

Answer 2

I ve run into issues sometimes with PHP not getting the correct path. Try getting your current working directory, then appending a relative path:

$im_path = dirname(__FILENAME__). /test/strawberry.png ;
$im = new imagick($im_path);