Question

What do T and S mean?
public void main(String... abc) ; what does ... mean? Is ... called generic as well?

Answer 1

That are parameterized types. You can use any identifier here to represent a certain object type.
That are varargs. You can pass a single String, or multiple Strings, or a String array in.

Answer 2

T and S are generic classes. They can be any type of class that you want. For example, Map<K, V> uses the K for the key class and V for the value class.

Map<Integer, String> map = new HashMap<Integer, String>

As for the String..., it means any number of String parameters.

Answer 3

Please read the documentation. Briefly, they are type parameters so that generic types and methods can know what type of objects they are acting on.
That indicates that the method can accept a variable number of arguments. See varargs. It s basically sugar around an array.

Answer 4

Sun s Java Generics documentation can be a bit hard to understand at times, so I tried to write a simpler tutorial on Java Generics. You can find it here:

http://tutorials.jenkov.com/java-generics/index.html

Answer 5

complementing: String... is almost the same as String[].
On the method side it is the same,
on the calling side the re is a difference: the compiler creates the array from the parameters.

void method(String... args) {
    // args is an array: getClass() returns [java.lang.String
    if (args.length >  0) {
        System.out.println(args[0]);
...
    method();               // same as method(new String[0]);
    method("1", "2", "3");  // same as method(new String[] {"1", "2", "3"});

Answer 6

T and S means that the class itself does not know what classes they are, but things that use the class do.

Take java.util.List. The list class does not know anything about T and makes no assumptions about T. Things that use the List class:

List<MyBean> l = new ArrayList<MyBean>();

Know what s in it.

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