是否有PHP功能将自动做到这一点?
if (is_array($array)) {
$obj = new StdClass();
foreach ($array as $key => $val){
$obj->$key = $val;
}
$array = $obj;
}
是否有PHP功能将自动做到这一点?
if (is_array($array)) {
$obj = new StdClass();
foreach ($array as $key => $val){
$obj->$key = $val;
}
$array = $obj;
}
为什么不光投它呢?
$myObj = (object) array("name" => "Jonathan");
print $myObj->name; // Jonathan
如果是多层面的,Richard Castera提供以下解决办法: 。
function arrayToObject($array) {
if(!is_array($array)) {
return $array;
}
$object = new stdClass();
if (is_array($array) && count($array) > 0) {
foreach ($array as $name=>$value) {
$name = strtolower(trim($name));
if (!empty($name)) {
$object->$name = arrayToObject($value);
}
}
return $object;
} else {
return FALSE;
}
}
如果它是一个一派阵列,那么一派应当发挥作用:
$obj = (object)$array;
对我的工作
if (is_array($array)) {
$obj = new StdClass();
foreach ($array as $key => $val){
$key = str_replace("-","_",$key)
$obj->$key = $val;
}
$array = $obj;
}
• 确保不允许在变式名称中选取方位;
变现规则
* A variable name must start with a letter or an underscore "_"
* A variable name can only contain alpha-numeric characters and underscores (a-z, A-Z, 0-9, and _ )
* A variable name should not contain spaces. If a variable name is more than one word, it should be separated with an underscore ($my_string), or with capitalization ($myString)
因此,由于这些阵列是允许的,如果其中任何一个是在你正在转换的阵列的钥匙上,那么你就会有新生错误。
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