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MSBuild: Conditional Construct (Project Reference | File Reference)
原标题:

I´m still trying to eleminate the need of a cobol compiler in a Project with cobol-Projects in it.

Is it possible to create following build behaviour:

If the Configuration is Debug then use ProjectReferences on ExCobol.cblproj if the Configuration is DebugVB then use FileReferences on ExCobol.dll

When Yes, How to achieve it?

I assume the use of tags in the project file will do the trick.

And does this really eliminate the need of a cobol compiler for the DebugVB Configuration?

最佳回答

Regarding the conditional how , assuming you have either

<ProjectReference ...>...</ProjectReference>

or

<Reference ...>...</Reference>

you want to hand-edit the .proj file to include both thusly

<ProjectReference Condition=" $(Configuration) != DebugVB " ...>...</ProjectReference>
<Reference Condition=" $(Configuration) == DebugVB " ...>...</Reference>
问题回答

Almost forgot this question: the answer from Brian works perfectly for me.

And to answer the second part of the question:

It indeed eliminates the need for a cobol compiler on every maschine if you setup different Configurations.

Thanks Brian.





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