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原标题:dynamically make top div position

因此,我制作了一个简单的日历(。 http://www.akapa.org/newsite/events/calendar.htm,我有一间“Morefo”但tons I从囚室接手。 在一片右边的桌子里,一把“MoreInfo” but子滚动时,全都看上去,这显然提供了日历日/通风的更多细节。

我的问题是,我每次在日历上增加一次新活动时,必须给每一个隐藏的四分之一提供准确的“顶”位置。 我想动态地告诉每个隐蔽的小区,以便与每个“Morefo”县的最高位置相匹配。 我如何这样做?

问题回答

您应使用rel=“nofollow noreferer”>。 Query;它使Javascript更容易。

您可以用 j子写如下:

$( #  + popupId).top($( # +tdId).offset().top);




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