我的朋友问我一个虚拟功能问题。
如果儿童反对将虚拟功能称为虚拟功能,那么这种虚拟功能实际上是在父亲执行中完成的?
我的朋友问我一个虚拟功能问题。
如果儿童反对将虚拟功能称为虚拟功能,那么这种虚拟功能实际上是在父亲执行中完成的?
我认为,你需要张贴一些法典,以澄清你要求的内容,但(除校长外)除非儿童明确要求其履行自己的职责,否则不会叫上基础职能。 例如:
struct A {
virtual ~A() {}
virtual void f() {}
};
struct B : public A {
virtual void f() {}
};
int main() {
A * a = new B;
a->f();
delete a;
}
只有B的虚拟功能 f()被点名。 如果你想要A:f()要求你明确:
struct B : public A {
virtual f() {
A::f(); // explicit call
}
};
在B没有宣布职能的情况下,当然还有奥赫,在这种情况下,A:f()总是被叫来。
不可能理解问题在目前形式中的确切含义。
如果从字面上讲,问题有明显和立即的答案:如果父母的履行是有关职能的最终压倒者,即儿童没有执行自己的职责,则要求父母的版本。
class parent {
public:
virtual void foo() { /* whatever */ }
};
class child : parent {
public:
void bar() {
foo(); /* call the parent s implementation, as requested */
}
};
因此,请你回答。
当然,对任何人来说,这种解释是显而易见的,他们很可能不是问题所暗示的。 很可能意味着子女阶级优先于父母的职能。 在该案中,还有另一个明显的答案:如果儿童使用完全合格的职务名称,将叫作母体。
class parent {
public:
virtual void foo() { /* whatever */ }
};
class child : parent {
public:
virtual void foo() { /* whatever */ }
void bar() {
parent::foo(); /* call the parent s implementation, as requested */
}
};
另一种可能的答案是,被称之为功能的物体实际上有<条码>。
class parent {
public:
virtual void foo() { /* whatever */ }
};
class child : parent {
public:
virtual void foo() { /* whatever */ }
void bar() {
parent p;
p.foo(); /* call the parent s implementation, as requested */
}
};
同样,它认为,这不是问题。 很可能,问题在于建筑商和司机发出的虚拟电话。
class parent {
public:
parent() {
foo(); /* always calls `parent::foo` */
}
virtual void foo() { /* whatever */ }
};
class child : parent {
public:
child() : parent() /* `parent::parent` will call `parent::foo` */
{}
virtual void foo() { /* whatever */ }
};
然而,由于这一问题的措辞不正确。 在发出呼吁时的最后一个例子中,还没有儿童目标。 它的记忆已经分配,但其寿命尚未开始。 说虚拟功能的电话由儿童对象履行是不正确的。 系由母物体执行。
因此,为了恢复上述工作:问题措辞模糊不清,措辞模糊不清,没有意义。
Base::f();
)如果这一举动是想方的,则发送将是静态的。 http://cplus.co.il/2009/09/30/virtual-dissuing-within-a-ructor-or-a-destructor/“rel=“nofollow noreferer”>http://cplus.co.il/2009/09/30/virtual-dispading-within-a-ructor-or-a-destructor/
第一条的例子涉及:
struct A {
A () { f(); }
virtual void f () { }
};
struct B : A {
B () :member(0) {}
void f () { std::cout << member; }
private:
int member;
};
int main () {
B b;
return 0;
}
援引的f是A:f,尽管事实上它是虚拟的,并且是由具有自己执行的B类物体所呼吁的。
如果儿童班子被叫走,那么该目标现在就属于父母的类型,因此,父母的虚拟功能将被称作。
已经提供了答复,这可能在施工期间发生:
这可能也是偶然的错误来源,因此特别注意建筑商和建筑;基类纯粹的虚拟方法;)
http://support.microsoft.com/kb/125749”rel=“nofollow noreferer”>http://support.microsoft.com/kb/125749
class A;
void fcn( A* );
class A
{
public:
virtual void f() = 0;
A() { fcn( this ); }
};
class B : A
{
void f() { }
};
void fcn( A* p )
{
p->f();
}
// The declaration below invokes class B s constructor, which
// first calls class A s constructor, which calls fcn. Then
// fcn calls A::f, which is a pure virtual function, and
// this causes the run-time error. B has not been constructed
// at this point, so the B::f cannot be called. You would not
// want it to be called because it could depend on something
// in B that has not been initialized yet.
B b;
void main()
{
}
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