var x01 = -712 + x04x05();
for (x01 = eval("x01") + 242; eval("x01") == 765; x01 = eval("x01") - 27)
{
}
这一有效行动是否成文? 如果是,情况如何?
var x01 = -712 + x04x05();
for (x01 = eval("x01") + 242; eval("x01") == 765; x01 = eval("x01") - 27)
{
}
这一有效行动是否成文? 如果是,情况如何?
而且,如果提交行动文本,则可能does工作。
它对变数和功能使用奇怪的识别符号当然是一致的。 这意味着,这几乎肯定是通过某种混淆者进行的,使你更难以做些什么(这是我的猜测,但我可能是错误的)。
我并不完全相信,由于在<<<>条码/代码>的路程上没有尸体,它目前的形式没有任何用处。 但守则本身似乎:
x01
to whatever the function x04x05()
returns less 712.x01
until it s not 765 (these seems unusual - terminating conditions are usually inequalities rather than equalties - in this case it seems that the loop will only execute once since you change x01
each time through the loop).基本上,用过时的代码,你只能用更敏感的识别符号来取代已经过时的识别资料,看看看是否有意义。 这是理解守则的良好的第一步(但可能不是所需的唯一步骤)。
如果像SWFEncode这样的产品,那么这一产出并不反映守则中实际发生的内容被混淆和加密。 我在实例之前/之后就看到了,至少从编辑的角度来看,它没有产生什么 r或理由。 除非你有办法对双亲进行加密,否则几乎没有机会进行倒置。
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