Question

page.getByXPath("//*[@href= http://www.example.com/index.do/abc/1_* ");

Do I need to escape any characters?

I am trying to get all ahref links on the page that have the pattern of:

http://www.example.com/index.do/abc/1_

so these should all be retrieved:

http://www.example.com/index.do/abc/1_asdf-asdfasdf
http://www.example.com/index.do/abc/1_223
http://www.example.com/index.do/abc/1_as.php
http://www.example.com/index.do/abc/1_2222233

Answer 1

There are no wildcards in XPath. You want something like this instead:

page.getByXPath("//*[contains(@href, http://www.example.com/index.do/abc/1_ )]");

This relies on the contains function. You can also use the starts-with function:

//*[starts-with(@href, http://www.example.com/index.do/abc/1_ )]

Answer 2

If you are using XPath 1.0, you cannot do wildcard (or regular expression) matches in that way. (Upgrading to 2.0 may allow that)

For this case, I d suggest doing a contains test for the prefix

//a[contains(@href, http://www.example.com/index.do/abc/1_ )]

(Note, I limited the select to just a tags)

Answer 3

See if your XPath library supports starts-with(string1,string2) and use:

page.getByXPath("//*[starts-with(@href,  http://www.example.com/index.do/abc/1_ )");

Also, can t you replace * by a ?

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