我的表格如下:
<table ..... class="cars">
<tr class="item-odd">
...
</tr>
<tr class="item-even">
</tr>
</table>
我如何利用Xpath接过桌子?
//tr[contains(@class, ???)
我可以在那里用某种方式使用OR表示项目-奇特里-7。
你们可以这样感动:
//table[@class= cars ]/tr
为了获得奇数增长,你将这样做:
//table[@class= cars ]/tr[@class= item-odd ]
是的,可使用<代码>或。 e.g:
//table[@class= cars ]/tr[@class= item-odd or @class= item-even ]
http://www.w3.org/TR/xpath"rel=“noretinger” http://www.w3.org/TR/xpath。
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