Question

I have a Visual Studio Code extension I m writing that uses the workspace folder path (File > Open Folder) to determine the base directory to run shell commands from. I can get the path from vscode.workspace.workspaceFolders[0].uri.path, but it causes problems when I use it with fs.readdir() because it s repeating the drive letter at the beginning.

Error: ENOENT: no such file or directory, scandir  C:c:UsersDaveDesktopESP Labs

Notice the extra C:

I would like to find a way to convert the URI path to a suitable filesystem path that will work with fs.readdir(). I tried url.fileURLToPath() but it didn t work and actually caused the extension to stop functioning until I commented out the console.debug line where I tried to display the result.

There s also a property called vscode.workspace.workspaceFolders[0].uri._fspath This does what I want, but I m thinking the underscore indicates the property is private and should not be used directly.

So my question is this...

Is there a method to convert uri.path to a filesystem path or should I just forget about it and use uri._fspath?

The code:

/*
 *  Copy entire project directory to remote flash file system. 
 */
let syncCommand = vscode.commands.registerCommand( mpremote.sync , async () => {
    if (!vscode.workspace.workspaceFolders || vscode.workspace.workspaceFolders.length != 1) {
        vscode.window.showErrorMessage( Unable to sync. Open a folder first. )
    }
    else {
        console.debug( vscode.workspace.workspaceFolders[0] , vscode.workspace.workspaceFolders[0])
        console.debug( uri._fsPath: , vscode.workspace.workspaceFolders[0].uri._fsPath)
        //console.debug( url.fileURLToPath: , url.fileURLToPath(vscode.workspace.workspaceFolders[0].uri.path))
        let projectRoot = vscode.workspace.workspaceFolders[0].uri._fsPath
        console.debug( Project folder path: , projectRoot)
        let port = await getDevicePort()
        term.sendText(`cd  ${projectRoot} `)
        fs.readdir(projectRoot, { withFileTypes: true }, (err, entries) => {
            if (err) {
                console.error(err)
                vscode.window.showErrorMessage( Unable to read directory. )
            }
            else {
                console.debug( Directory entries found: , entries.length)
                entries.forEach(entry => {
                    console.debug( Examining directory entry: , entry)
                    if (entry.isDirectory()) {
                        if (SYNC_IGNORE.includes(entry.name)) {
                            console.debug( Skipping directory: , entry.name)
                        }
                        else {
                            term.sendText(`${PYTHON_BIN} -m mpremote connect ${port} fs cp -r ${entry.name} :`)
                        }
                    }
                    else {
                        term.sendText(`${PYTHON_BIN} -m mpremote connect ${port} fs cp ${entry.name} :`)
                    }
                })
            }
        })
    }   
})

Debug output showing available uri properties:

vscode.workspace.workspaceFolders[0] {uri: v, name:  ESP Labs , index: 0}
vscode.workspace.workspaceFolders[0] {
  uri: v {
    scheme:  file ,
    authority:   ,
    path:  /c:/Users/Dave/Desktop/ESP Labs ,
    query:   ,
    fragment:   ,
    _formatted:  file:///c%3A/Users/Dave/Desktop/ESP%20Labs ,
    _fsPath:  c:\Users\Dave\Desktop\ESP Labs 
  },
  name:  ESP Labs ,
  index: 0
}
uri._fsPath: c:UsersDaveDesktopESP Labs
Project folder path: c:UsersDaveDesktopESP Labs

Answer 1

Well, there is a vscode.workspace.workspaceFolders[0].uri.fsPath property you could use - note no underscore. It returns the same thing as the _fsPath property.

See vscode api docs: Uri.

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