suppose i have the following in a text file (or dired buffer) open in emacs: file_01.txt file_02.txt ... file_99.txt
I want to query-replace or replace the files to 01_file.txt, etc.
我想使用查询或替代登记,但不知道什么。 检索部分一载于“档案-......”,但“......”改为替代体中的时段。 我开始学习,不知道如何这样做。 请提供帮助。
<代码>M-x 替换-regexp 援引以常规表述取代的功能。
<(file)_[0-9]+
这将设立两个小组,一个与档案部分相对应,另一个与数字相匹配。 布拉斯(......)是稍后在更换舱内提供校对的必要。
<<>Replace with into:2_1
这加上了从搜索线(数字部分)中得出的第二比,增加了__(低于分数),然后增加了从搜索线(档案)中得出的第一比。
关于Emacs常规表述的更多信息,见Regexpyntax和。
一旦你掌握了格列克式基本原理,你可能希望检查一下:。
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