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dividing the image into four equal parts in JAI
原标题:
  • 时间:2010-02-03 09:10:42
  •  标签:
  • java
  • imaging

please give me the coding for dividing the image into four parts from the center in Java Advanced Imaging..

问题回答

Not sure about JAI, but here s the BufferedImage approach which you might use as an input for JAI. So maybe this works for your usecase

public static BufferedImage[] divide(BufferedImage source) {
  // for odd widths or heights, the last row or column will be ignored
  // fixing this behaviour is left as an exercise to the eager
  int height = source.getHeight() / 2;
  int width = source.getWidth() / 2;

  return new BufferedImage[] {
    source.getSubimage(0, 0, width, height), // top left
    source.getSubimage(width, 0, width, height), // top right
    source.getSubimage(0, height, width, height), // bottom left
    source.getSubimage(width, height, width, height) // bottom right
  };
}

There s an interesting bit of trompe-l oeil in Sun s Java2D* demo using four unequal parts.

* See the lower, right quadrant of the Images tab.

In the example the width must come first than the height. That is:

source.getSubimage(0, 0,width, height ), // top left
source.getSubimage(width, 0, width, height), // top right
source.getSubimage(0, height, width, height), // bottom left




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