我正在做一道作业题,但是在创建一个O(n*logn)的解决方案方面遇到了一些困难。我需要编写一个函数,该函数接受一个已预排序的数组和一个要搜索的值。接下来,我需要找到数组中是否有任何两个元素的总和等于该值。
我需要创建O(n)和O(n * logn)算法。
O(n)很容易创建;然而,我在创建O(n*logn)算法时遇到了困难,没有添加一些不实际有助于解决问题的不必要代码。如果有人可以给我一些提示,我将不胜感激。
我正在做一道作业题,但是在创建一个O(n*logn)的解决方案方面遇到了一些困难。我需要编写一个函数,该函数接受一个已预排序的数组和一个要搜索的值。接下来,我需要找到数组中是否有任何两个元素的总和等于该值。
我需要创建O(n)和O(n * logn)算法。
O(n)很容易创建;然而,我在创建O(n*logn)算法时遇到了困难,没有添加一些不实际有助于解决问题的不必要代码。如果有人可以给我一些提示,我将不胜感激。
从第一个元素开始,顺序前进。在此过程中,使用二分搜索查找第二个元素。
由于它们是预先排序的,您可以使用二进制搜索和线性搜索。
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