Sayuser has_many 情况。 在用户表格中,我喜欢一个隐蔽的现场,让我在这个新用户与先前存在的Thing之间建立起一种关系,即近8。 以下法典有什么错误? 我认为,我只是想在这里看到一些辛子。
<% f.hidden_field things[] , :value => 8 %>
<% f.hidden_field thing_id[] , :value => 8 %>
员额...... 如果您对需要寄给服务器的仪器具有多种价值,那么,这里如何做到:
<% user.things.each do |thing| %>
<% f.hidden_field thing_ids][ , :value => thing.id %>
<% end %>
1. 将倒置的括号与内容联系起来。 如果括号内的服务器没有倒置,则服务器有2件。 随着方括号的倒置,你会在寄生虫阵列中获得正确的东西。
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