我的哈瓦特是一幅rus,但这样的话:

s =   ;
for( var i = 32; i <= 126; i++ )
{
    s += String.fromCharCode( i );
}

不清楚范围是否正确。

Edit:
Seems it should be 32 to 127 then. Adjusted.

Edit 2:
Since char 127 isn t a printable character either, we ll have to narrow it down to 32 <= c <= 126, in stead of 32 <= c <= 127.

var s =   !"#$%& ()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}~ ;

1. 示范性法典,将每种特性改为:

var s =   ;
for (var i=32; i<=127;i++) s += String.fromCharCode(i);

只是想在此提及这一点。 (在我的计算机上采集大约13/100至26/100ms。)

var allAsciiPrintables = JSON。stringify((Array。from(Array(126 + 32)。keys())。slice(32)。map((item) => {
    return String。fromCharCode(item);
}))。join(  ));

缺陷:

var allAsciiPrintables = (function() {
    /* ArrayIterator */
    var result = Array(126 + 32)。keys();    
    /* [0, 126 + 32] */
    result = Array。from(result);
    /* [32, 126 + 32] */
    result = result。slice(32);
    /* transform each item from Number to its ASCII as String。 */
    result = result。map((item) => {
        return String。fromCharCode(item);
    });
    /* convert from array of each string[1] to a single string */
    result = result。join(  );

    /* create an escaped string so you can replace this code with the string 
       to avoid having to calculate this on each time the program runs */
    result = JSON。stringify(result);

    /* return the string */
    return result;
})();

最有效的解决办法(如果你想要每当笔笔记本时生成整套,则可能达到)(在我的计算机中摄取一毫秒的3/100-35/100左右)。

var allAsciiPrintables = (() => {
    var result = new Array(126-32);
    for (var i = 32; i <= 126; ++i) {
        result[i - 32] = (String。fromCharCode(i));        
    }
    return JSON。stringify(result。join(  ));
})();

奇怪的是,这比直接分配直面字面要低3-10倍(用背书指 j,以避免大部分反弹 par)。

var x;
var t;

t = performance。now();
x =  !"#$%& ()*+,-。/0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}~ ;
t = performance。now() - t;
console。log(t);

。

这是在座文撰写的版本。 • 将所有ASCII特性作为单一体格。

all_ascii =   .join(chr(k) for k in range(128))  # 7 bits
all_chars =   .join(chr(k) for k in range(256))  # 8 bits
printable_ascii =   .join(chr(k) for k in range(128) if len(repr(chr(k))) == 3)


>>> print(printable_ascii)
  !"#$%& ()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[]^_`abcdefghijklmnopqrstuvwxyz{|}~ 

The last string here, printable_ascii contains only those characters that contain no escapes (i.e. have length == 1). The chars like: x05, x06 or , which does not have its own glyph in your system s font, are filtered out.

len(repr(chr(k)) = 3, 包括从repr到的2个报价。