审查:rel=“noreferer” http://developer.android.com/vis/android/graphics/Canvas.html。
我很想知道
翻译:“将现有矩阵与特定的翻译混为一谈”——这意味着什么?
我在互联网上任何地方都找不到“前线”的良好定义! 我能找到的唯一地方是安乐施会——我开始问,他们是否站出来?
I m 熟悉“目录”或“组合”,这是为了证明,因此什么是预先目录?
审查:rel=“noreferer” http://developer.android.com/vis/android/graphics/Canvas.html。
我很想知道
翻译:“将现有矩阵与特定的翻译混为一谈”——这意味着什么?
我在互联网上任何地方都找不到“前线”的良好定义! 我能找到的唯一地方是安乐施会——我开始问,他们是否站出来?
I m 熟悉“目录”或“组合”,这是为了证明,因此什么是预先目录?
在与矩阵打交道时,“分类”一词指的是多重复。
Since matrix multiplication is not commutative, there is a separate word for backwards multiplication.
Pre-concatenating a
to b
means setting a = b × a
. (As opposed to a = a × b
, which will give a different matrix)
这只是谷歌及其发展的一个实例,是该守则中的文字和碎片。 如果我是提交人,我会为此处以罚款。 从根本上说,这意味着从正确方面增加现有的矩阵,因为在病媒改造中,右侧的矩阵首先移动,因此是“前”。 例如,如果你想要扩大形象,搬到另一个地点,那么你就应当做到:
mCanvas.translate(tx,ty);
mCanvas.scale(sx,sy);
mCanvas.drawBitmap(mBitmap,0,0,mPaint);
这与常识逻辑相反。
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