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PHP MySQLINSERT由于独特的制约因素而失败
原标题:PHP MySQL INSERT fails due to unique constraint

在插入上,我抓住了独特的制约因素。

这样做是值得称道的,但我想找到现有的行文,以恢复或修改。

是否有办法在“失败”之后获得流id? 我尝试了我的sql_insert_id(),但实现的只是将第1行插入(或未插入)的内容归还给我。

是否别无选择,只能再发行一盘 my,只是就重复价值进行选择?

我只想确保这样做没有更好、更快、更经济的方法。

最佳回答

如果你试图插入一行,如果是新的或更新现有的数值,那么。 另见, if there are restrictions involved as REPLACE INTO will DELETE and subsequently INSERT.

问题回答

您必须检查任何“unique”钥匙的表格(SHOW CREATE TABLE/code>将列出所有这些钥匙,然后询问你试图插入的有关数值的表格。 因此,如果你重新插入A、B、C、D和B、C等地对它们具有独特关键意义,那么:

SELECT id, B, C FROM table WHERE B=$B and C=$C;




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