当窗户被 s倒,但没有发生任何事情时,我正在使用这一代码来压倒形象。
$( #left_img ).css("top",$(window).scrollTop()+"px");
#left_img {
margin:0 0 0 -55px !important;
position:absolute;
top:5px !important;
}
如果能够发现整个电梯窗口的高度,那么如果图像达到某些高点,那么它就应当停止滑坡。
当窗户被 s倒,但没有发生任何事情时,我正在使用这一代码来压倒形象。
$( #left_img ).css("top",$(window).scrollTop()+"px");
#left_img {
margin:0 0 0 -55px !important;
position:absolute;
top:5px !important;
}
如果能够发现整个电梯窗口的高度,那么如果图像达到某些高点,那么它就应当停止滑坡。
你们需要首先抓住这次事件。
$(window).scroll(function() {
$( #left_img ).css("top", $(window).scrollTop()+"px");
});
我对滚动和定位知之甚少,但如果你不抓住这个事件,那可能是你再次出现的问题。
我想你们的笑话真是说了! 为什么你们的雕像(用javascript/jquery)?
你们都需要确定
#imageID
{
position: fixed;
left: 20px;
top: 20px;
}
它将浏览网页。 因此,用文字roll死的理由是什么?
使它成为一小 ne子;
$(window).scroll(function(){
var getbodyt = $(window).scrollTop();
var getbodyl = $(window).scrollLeft();
$("#left_img").css({top: getbodyt, left: getbodyl});
});
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