我正试图从扼杀中抽取一些东西。 这一数字可能是零。 这一数字似乎如下:+123、-8或0。
alert( +123 .match(/[-?|+?]d+/) );
alerts +123
alert( -8 .match(/[-?|+?]d+/) );
alerts -8
alert( 0 .match(/[-?|+?]d+/) );
alerts null // why oh why?
我怎样获得0.match(/[->+?]d+/)的回报,而不是取消?
我正试图从扼杀中抽取一些东西。 这一数字可能是零。 这一数字似乎如下:+123、-8或0。
alert( +123 .match(/[-?|+?]d+/) );
alerts +123
alert( -8 .match(/[-?|+?]d+/) );
alerts -8
alert( 0 .match(/[-?|+?]d+/) );
alerts null // why oh why?
我怎样获得0.match(/[->+?]d+/)的回报,而不是取消?
模式
[-?|+?]
准确对应的是<代码>-,+
,>> 或
?
。 你们想要的是
[-+]?
这与<代码>-或+
一或零倍。
这将使像123这样的数字也能通过。 如果你要求加标,则使用:
/0|[-+][1-9]d*/
这里
var rePattern = /[+-]?d+/;
"0".match(rePattern) // 0
"+44".match(rePattern) //+44
"-3".match(rePattern) //-3
注:这并不像Kenny s那样严格。
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