Question

如何在案文节中找到另一字之前和之后的字句?

Answer 1

I. In XSLT 2.x / XPath 2.x one can use the functions tokenize(和 -of(

<xsl:stylesheet version="2.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output method="text"/>

 <xsl:param name="pWord" select=" three "/>

 <xsl:template match="text()">
   <xsl:sequence select=
    "tokenize(.,  ,s* )
        [index-of(tokenize(current(),  ,s* ), $pWord) -1]"/>

   <xsl:sequence select=
    "tokenize(.,  ,s* )
        [index-of(tokenize(current(),  ,s* ), $pWord) +1]"/>
 </xsl:template>
</xsl:stylesheet>

www.un.org/Depts/DGACM/index_spanish.htm 在以下XML文件适用这一转变:

<t>One, two, three, four</t>

<t, 正确结果::

two four

II.XSLT 1.0 Solutions

可在XSLT1.0中利用<代码>Spstrlit-to-Words模板解决同一任务:SL。

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:ext="http://exslt.org/common"
>
   <xsl:import href="strSplit-to-Words.xsl"/>

   <xsl:output method="text"/>

   <xsl:param name="pWord" select=" three "/>

    <xsl:template match="/">
      <xsl:variable name="vrtfwordNodes">
        <xsl:call-template name="str-split-to-words">
          <xsl:with-param name="pStr" select="/"/>
          <xsl:with-param name="pDelimiters" 
                          select=" , &#9;&#10;&#13; "/>
        </xsl:call-template>
      </xsl:variable>

      <xsl:variable name="vwordNodes"
         select="ext:node-set($vrtfwordNodes)/*"/>

      <xsl:variable name="vserchWordPos" select=
      "count($vwordNodes
                 [. = $pWord]/preceding-sibling::*
             ) +1"/>

      <xsl:value-of select=
       "concat($vwordNodes[$vserchWordPos -1],
                  ,
               $vwordNodes[$vserchWordPos +1]
               )
       "/>
    </xsl:template>
</xsl:stylesheet>

www.un.org/Depts/DGACM/index_spanish.htm 当这一转变适用于同一XML文件时:

<t>One, two, three, four</t>

<t, 正确结果::

two four

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