问题似乎没有什么混淆。 因此,请允许我以一个例子说明我的情况:
Suppose I have an XML: A.xml
<Cakes>
<Cake>Egg</Cake>
<Cake>Banana</Cake>
</Cakes>
另一项XML:B.xml
<Cakes>
<Cake show="true">Egg</Cake>
<Cake show="true">Strawberry</Cake>
<Cake show="false">Banana</Cake>
</Cakes>
现在,我要表明一些案文:“TRUE”,如果在<代码>A.xml上的所有震动都有<代码>show=“true” in B.xml,否则“FALSE。
在上述情况下,它将印刷FALSE。
为此,我需要制定一部XSL。 如果汽车在B.xml显示“真实”,我可以穿透A.xml的所有面包车,如果发现显示“false”,我不知道如何在(和设定一个变数)之间断裂。
是否可能? 感谢任何帮助/帮助。
<xsl:choose>
<xsl:when test="count(document( B.xml )/Cakes/Cake[@show= true AND text() = /Cakes/Cake/text()]) = count(/Cakes/Cake)">
true
</xsl:when>
<xsl:otherwise>
false
</xsl:otherwise>
应帮助(不是100%)
这里的问题是,你可以更新SL的可变性;SL可变性只有一次签字,但可以有条件转让。
我认为,更简单、更明智的办法是使用小型的XSL碎片,从适当的方案拟订语言中将其从方案上说出来,这样可以使用XPath来进行消化。
我认为,最好的办法是:
www.un.org/Depts/DGACM/index_spanish.htm 是否至少有一个要素是“Cake”为“A.xml”,与“Cake”为“B.xml”,其属性是“thetrue”?。
因此,Xpath 1.0:
document(A.xml )/Cakes/Cake[not(not)(B.xml)/Cakes/Cake[@show= real)]
注:我对译文表示歉意。 我讲西班牙语。
www.un.org/Depts/DGACM/index_spanish.htm 正确评估这一状况的最简单的XPath表述之一是:。
not(document( B.xml )/*/Cake[@show != true ] = /*/Cake)
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