我确实有一个数据库,近11个表格。 虽然我的网页正在开放,但将同时从这11个表格中获取信息。 根据我目前的环境,我现在对每个桌子数据库所做的是开放和关闭。 Saye 我给每个桌子开放一个数据库的用户名和密码,并在从该表检索信息之后关闭。
这样做是否正确? 因此,我感到,数据库正在开放和关闭11次! 谁? 这是这样做的正确途径吗?
我确实有一些表格,其更新日期不同于其他表格。
我确实有一个数据库,近11个表格。 虽然我的网页正在开放,但将同时从这11个表格中获取信息。 根据我目前的环境,我现在对每个桌子数据库所做的是开放和关闭。 Saye 我给每个桌子开放一个数据库的用户名和密码,并在从该表检索信息之后关闭。
这样做是否正确? 因此,我感到,数据库正在开放和关闭11次! 谁? 这是这样做的正确途径吗?
我确实有一些表格,其更新日期不同于其他表格。
由于各表都在同一个数据库中,因此没有必要继续关闭和重新启用数据库。 Use mysql_joint 第一次,随后又发出如下呼吁:mysql_query,如果你不提供新的联系,将重新利用这一联系。
I noticed that there were some threads with similar questions, and I did look through them but did not really get a convincing answer. Here s my question: The subquery below returns a Table with 3 ...
<?php $con=mysql_connect("localhost","mts","mts"); if(!con) { die( unable to connect . mysql_error()); } mysql_select_db("mts",$con); /* date_default_timezone_set ("Asia/Calcutta"); $date = ...
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