Question

在我的网络应用中,已经存在或根本没有检查会议。

i 希望在我的服饰和 j中加以检查。

没有任何办法加以检查。

增编

Answer 1

http://java.sun.com/javaee/5/docs/api/javax/servlet/http/HttpServletRequest.html#getSession%28boolean%29”rel=“n或etinger”HttpServletRequest#Session(bean Creat) with create=false 。如果尚未建立,它就会失去效力。

HttpSession session = request.getSession(false);
if (session == null) {
    // Session is not created.
} else {
    // Session is already created.
}

如果您确实想在届会的某一点上开车,那么就只是 gr,并且用HttpSession#is New(:

HttpSession session = request.getSession();
if (session.isNew()) {
    // Session is freshly created during this request.
} else {
    // Session was already created during a previous request.
}

这正是你在《服务手册》中所做的。在一项共同财产调查中,你只能在共同财产法和EL的帮助下检验新鲜。 http://java.sun.com/javaee/5/docs/api/javax/servlet/jsp/PageContext.html#getSession%28%29”rel=“n或eferer”>:, 之后仅打电话。

<c:if test="${pageContext.session.new}">
    <p>Session is freshly created during this request.</p>
</c:if>

或

<p>Session is ${pageContext.session.new ?  freshly  :  already } created.</p>

Answer 2

一种办法是在小屋内开课,然后在另一个小屋或小屋子里检查同一届会议,以检查是否活着。

HttpSession session = req.getSession();
        session.getId();

友情链接