Question

I need a help with setting a random image using setImageResource method. In the drawable folder, I have a jpeg file named photo0.jpg, photo1.jpg...photo99.jpg. And the following code works:

int p = R.drawable.photo1;
image.setImageResource(p);

The above will display photo1.jpg but I want to show a random image. I tried the following but it doesn t work.

String a = "R.drawable.photo";
int n = (int) (Math.random()*100)
String b = Integer.toString(n);
String c = a+b;
int p = Integer.parseInt(c);//checkpoint
image.setImageResource(p);

It seems like the string "R.drawable.photoXX" isn t being changed to integer at the checkpoint. Could someone please teach me a right code? Thank you in advance.

Answer 1

在这项工作方面,由于间接费用,优势是巨大的。由于Anderson已经给你带来了愤怒,因此我建议将所有这些都储存到一个阵列,然后使用随机编号来编制指数。

该法典将探讨这样的问题:

int imageArr[] = new int[NUM_IMAGES]; 

imageArr[1] = R.drawable.photo;

//(load your array here with the resource ids)

int n = (int)Math.random()*NUM_IMAGES;

image.setImage(imageArr[n]);

在这里,我们非常直截了当地实施,绕过了随着扼杀事件而产生的所有创造和破坏。

Answer 2

这里的错误可能是:

注

页: 1

int n = (int) (Math.random(%100)

接收所有100岁以下人员

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