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我目前开始学习使用Java编程。我试图在Java中编写出题目中的序列作为输出，但我卡住了！我正在尝试使用for函数进行实验，欢迎任何帮助;)

Answer 1

System.out.println("1 0 1 0 0 1 0 0 0 1 0 0 0 0 1 0 0 0 0 0");

但说真的，各位，这只是一个未经测试的初步尝试：

for(int i=1; i<100; i++){
    System.out.print("1 ");
    for(int j=0; j<i; j++){
        System.out.print("0 ");
    }
}

如果你正在寻找如何入门的基本信息，Google就是你的好朋友。例如，尝试在Google上搜索“for loop java”，你将得到很多好的示例。另外，在任何语言中学习基本事物，搜索“ hello world”非常可靠。

Answer 2

为什么两个循环？

（从C#转换，原谅任何语法错误）

String s = "1 ";
for (int i = 0; i < 5; ++i)
{
  s = s + "0 ";
  System.out.print(s);
}

自我批评

two for loops (like Michael Haren s solution) would negate the string copying
a StringBuffer/StringBuilder would negate the string copying

Answer 3

你可以将数字“10”存储在一个变量中，在循环中打印该数字，将其乘以10（这会在其小数表示中附加一个零），然后重复以上步骤。

Answer 4

for (int i = 2; i < 64; i <<= 1)
    //System.out.print(Integer.toString(i, 2));
    System.out.print(Integer.toString(i, 2).replaceAll("[01]", "$0 "));

Answer 5

This is not really a question of fors but rather of very rudimentary algorithmic thinking. You have a sequence that consists of a "1", and then something else that grows over time", another "1", another something, etc. You can think of these as two different series that are interleaved.

因此，总体结构应该是这样的：

while(... infinity?)
{
   System.out.print("1");
   doSomething(); 
}

现在，某些东西显然与外循环的迭代次数（“阶段”）或1的计数相关，因此您需要类似以下的东西：

int stage=0;
while(...infinity?)
{
   ++stage;
   System.out.print("1");
   for(int i=0; i<stage; ++i) System.out.print("0");
}

如果您知道需要多少个周期，请使用for循环而不是while，并通过它增加阶段。

Answer 6

Or did your teacher ask you to? Two nested for loops will do the trick.

或者用另一种语言（Ruby）的另一种方式：

4.times {|n| print 10**(n+1)}

Answer 7

f或者 (huòzhě) (int i = 1; i < 100000;)
{
    i = i * 10;
    System.out.print(i);              
}

或者 (huòzhě)

int i = 1;

while (i < 100000)
{
    i = i * 10;
    System.out.print(i);
}

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