Question

我的问题与

var ids = "1*2*3";
var Name ="John*Brain*Andy";
var Code ="A12*B22*B22";

现在,我有一系列 j。我想根据<代码>CODE分类我的物体。因此,该法典中可能出现重复编码。

根据上述变化,我有相同的脑和安迪守则。因此,现在我需要两个阵列。只有一个目标只包含John的细节,另一个目标中将有两个目标,包括脑和安迪的细节。

举例来说,我只拿了3个项目。在实践中,可能有许多不同的守则,也可能有许多不同的守则。

UPDATE
I needed the structure like the one built in groupMap object by the @Pointy. But I will use @patrick s code to achieve that structure. Many thanks to both of them.

Answer 1

很难告诉你所需要的确切结构。

该法典:

       // Split values into arrays
Code = Code.split( * );
Name = Name.split( * );
ids = ids.split( * );

       // cache the length of one and create the result object
var length = Code.length;
var result = {};

       // Iterate over each array item
       // If we come across a new code, 
       //    add it to result with an empty array
for(var i = 0; i < length; i++) {
    if(Code[i] in result == false) {
        result[ Code[i] ] = [];
    }
            // Push a new object into the Code at "i" with the Name and ID at "i"
    result[ Code[i] ].push({ name:Name[i], id:ids[i] });
}

形成这一结构:

// Resulting object
{
      // A12 has array with one object
    A12: [ {id: "1", name: "John"} ],

      // B22 has array with two objects
    B22: [ {id: "2", name: "Brain"},
           {id: "3", name: "Andy"}
         ]
}

Answer 2

Split the strings on "*" so that you have 3 arrays.
Build objects from like-indexed elements of each array.
While building those objects, collect a second object that contains arrays for each "Code" value.

法典:

function toGroups(ids, names, codes) {
  ids = ids.split( * );
  names = names.split( * );
  codes = codes.split( * );
  if (ids.length !== names.length || ids.length !== codes.length)
    throw "Invalid strings";

  var objects = [], groupMap = {};
  for (var i = 0; i < ids.length; ++i) {
    var o = { id: ids[i], name: names[i], code: code[i] };
    objects.push(o);
    if (groupMap[o.code]) {
      groupMap[o.code].push(o);
    else
      groupMap[o.code] = [o];
  }
  return { objects: objects, groupMap: groupMap };
}

你们说,“两阵”是你想要的,是该功能归还的物体的“集体”财产。

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