say A = rand(2,2,2); [a,b,c] = find(A == A(1,2,2))
I got a=1 b=4 c=1
什么?
只有在你重新尝试对2个层面阵列适用时,才会奏效。
马塔布中央有少数职能,将设一席。
使用平等<条码>=,而不是转让操作人<条码>=。
A = rand(2,2,2); [a,b,c] = find(A == A(1,2,2))
See documentation for FIND.输出论点并非针对所有方向,仅指行和栏。 看来MATLAB在第2栏和第4栏回归线上压缩了第3方向。 最后一个论点等于1,因为只有一对。
FIND的功能是两套指数(a和b)和这些指数的数值(c)。 关于2个以上的矩阵,第二个指数是linearindex。
举例来说,你在<代码>A = A(1,2,2)时,就形成了一个合乎逻辑的阵列。 这一逻辑阵列的价值为1(即true,载于索引(1,2,2),现通过rel=“nofollow noreferer”>FIND 功能。 这一非零值的位置在矩阵的第一行(产出<代码>a = 1)和其余部分(产出<编码>b = 4)内的第四行指数。 <代码>1的非零值为<代码>c的产出。
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