Question

BC1024 , AB124 , CBC2548 ,

采用序号,将编号和特性分开,

为此,我尝试了这一先令的表达方式,但并未开展大量工作。

preg_match_all( /(?Pw+): (?Pd+)/ , $flight_code_no, $matches,PREG_PATTERN_ORDER);

i 想要产出

Array
(
    [0] => BC1024: 2008
    [name] => BC
    [1] => BC
    [digit] => 1024
    [2] => 1024
)

但是,我的预言不行......。

只是空洞阵列,

Answer 1

preg_match( /(?<name>[A-Z]+)(?<digit>d+)/ ,  BC1024 , $result);

说明

Array
(
    [0] => BC1024
    [name] => BC
    [1] => BC
    [digit] => 1024
    [2] => 1024
)

Answer 2

仅表明,你不需要先做事,才能把简单地描述成:

list($name,$digit) = sscanf($flight_code_no, %[A-Z]%d );

Answer 3

驾驶

<?php

foreach (array("BC1024", "AB124","CBC2548") as $v) {
  preg_match_all("/(?P<name>[A-Z]+)(?P<digit>d+)/", $v, $matches); 
  var_dump($matches);
}

产出(一些新路线改写)

array(5) {
  [0]=>       array(1) {    [0]=>    string(6) "BC1024"  }
  ["name"]=>  array(1) {    [0]=>    string(2) "BC"  }
  [1]=>       array(1) {    [0]=>    string(2) "BC"  }
  ["digit"]=> array(1) {    [0]=>    string(4) "1024"  }
  [2]=>       array(1) {    [0]=>    string(4) "1024"  }
}
array(5) {
  [0]=>       array(1) {    [0]=>    string(5) "AB124"  }
  ["name"]=>  array(1) {    [0]=>    string(2) "AB"  }
  [1]=>       array(1) {    [0]=>    string(2) "AB"  }
  ["digit"]=> array(1) {    [0]=>    string(3) "124"  }
  [2]=>       array(1) {    [0]=>    string(3) "124"  }
}
array(5) {
  [0]=>       array(1) {    [0]=>    string(7) "CBC2548"  }
  ["name"]=>  array(1) {    [0]=>    string(3) "CBC"  }
  [1]=>       array(1) {    [0]=>    string(3) "CBC"  }
  ["digit"]=> array(1) {    [0]=>    string(4) "2548"  }
  [2]=>       array(1) {    [0]=>    string(4) "2548"  }
}

友情链接