Im implementing the shunting-yard算法。 我在找不到对经营者的争论时会发现问题。 wikipedia 。 这一主题非常糟糕,其法典也坠毁了下文的例子。
例如,3 - (5 + )是不正确的,因为+没有争论。
在算法达到<代码>>之前,操作员栏目中包含<代码>-(+,歌剧中包含3 5。 接着,情况如下:
+ from the operator stack+ is a binary operator8) to operand stack( from the stack, and continues因此,我如何能够发现<代码>+<>/code>是没有论据的? 额外库库多斯(如果你也更新):
对双轨操作员来说,固定式的表述总是在any的表述前、操作编号和编号上;操作者人数和最终的区别完全相同。
因此,你可以通过维持一定数目的歌剧——操作者人数——来核实尼泊尔共产党在紧凑的院子的每一阶段是否有效。 如果下降幅度低于1,或最终超过1,则有错误。
它没有指明错误,但至少让你知道有错误。
(说明:我曾尝试过证明上述事实,但似乎喜欢这样做)
你可以建造一台国家机器。 它可以发现有错之处。
When you start reading the expression expect a prefix operator or an operand. If you read a prefix operator expect a prefix operator, operand or opening parenthesis.
如果你阅读一个歌剧,就会发现一个固定或固定操作者或封闭的母体。
如果你读到一个固定员额操作员,期望固定操作者或封闭式母体。
如果你读到固定操作员,则期望有固定操作员、操作员或开母。
如果你阅读了开端的括号,预期会有一名固定操作员、操作员或开母。
如果阅读了结对的括号,就期望有一个固定或固定操作者或封闭的母体。
如果能够很容易地转换,你可以这样做:
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