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最合理的方式是在法体中rag死。
原标题:most rational way to drag popup menu in flex

在我的附录中,我目前作为边界过境点执行了一个人口菜单,其中有许多县、文字区、日期采集器等。 PopUpManager根据一些情报和安全局的活动处理其出现和消失的问题。

我愿对集装箱的任何部分点击minus。 换言之,当我点击纽州、文本领域等时。 我恳请他们像往常一样作出回应,而集装箱则不能卸下。

我尝试了这一非常简单的执行。

_menu.addEventListener(MouseEvent.ROLL_OVER, toggleDragON);
_menu.addEventListener(MouseEvent.ROLL_OUT, toggleDragOFF);

private function mouseDown(event:MouseEvent):void 
{ 
    _menu.startDrag(); 
} 

private function mouseReleased(event:MouseEvent):void 
{ 
    _menu.stopDrag(); 
}

但是,这无疑是trick的,即所有组成部分都会导致拖累。 我试图确保,所有组成部分都适用变幻剂和恶性,但这似乎没有任何改变。

接着我来过。 这一版的意义很大,但我有很强的时间认为,处理该问题的最佳途径是处理每一组成部分的点击事件。 是否有明显简单的办法来做到这一点。

谢谢!

f

最佳回答

如何检查活动的目标财产,以检查是否等于你的菜单?

if (event.target == _menu) {
    _menu.startDrag();
}
问题回答

暂无回答




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