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PHP收到信函
原标题:PHP get the letter

缩略语:

"Elton John"
"2012"
" George Bush"
" Julia"
"Marry III Great"

须打上<代码>第1封信的编号,并添加到<代码>字母变量上。

说明中有多少字(分为“空间”):

  1. 如果只有一个字,则在第一字的第一封信中打上$

  2. 如有不止一个字,则在第二字的第一封信中插入$

  3. <代码> 姓名为空档,$letter未定义的

感谢。

最佳回答
$names = explode(   , trim($name));
if (empty($names))
    $letters =  undefined ;
else if(count($names)==1)
    $letters = substr($names[0],0,1);
else 
    $letters = substr($names[1],0,1);
问题回答

你们只能做一次探索或预想,并算出:

$parts = preg_split( /s/ , $subject, -1, PREG_SPLIT_NO_EMPTY);
if (count($parts) == 1)
   ...

a. 探索的替代物:

$subject = trim(subject);
$parts = explode(   , $subject);

如果你确定只有空间,这种工作也会发生。

或者说,你只能使用

$letter = $name{0};




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