I need to load a yaml file into Hash,
What should I do?
Use the YAML module:
http://ruby-doc.org/stdlib-1.9.3/libdoc/yaml/rdoc/YAML.html
node = YAML::parse( <<EOY )
one: 1
two: 2
EOY
puts node.type_id
# prints: map
p node.value[ one ]
# prints key and value nodes:
# [ #<YAML::YamlNode:0x8220278 @type_id="str", @value="one", @kind="scalar">,
# #<YAML::YamlNode:0x821fcd8 @type_id="int", @value="1", @kind="scalar"> ]
# Mappings can also be accessed for just the value by accessing as a Hash directly
p node[ one ]
# prints: #<YAML::YamlNode:0x821fcd8 @type_id="int", @value="1", @kind="scalar">
rel=“noreferer” http://yaml4r.sourceforge.net/doc/page/parsing_yaml_documents.htm
我想用的是:
hash = YAML.load(File.read("file_path"))
简便易货答案:
hash = YAML.load_file("file_path")
您可能会陷入上所提到的问题,即,国际奥马法分子的档案或溪流明确了一种目标,即国际奥马法分子的装载者将试图将数据转换成。 问题是,你们将需要一个了解有关物体的相关宝石。
我的解决方案是十分棘手的,是作为这一问题的答案而提供的。 这是:
yamltext = File.read("somefile","r")
yamltext.sub!(/^--- !.*$/, --- )
hash = YAML.load(yamltext)
实质上,你将目标级文字从半年文中删除。 之后,你便服/卸下。
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