Question

我期待着:

array($ID => array (name => $name, created => $timestamp))

e.g

[5632][name] = martin
[5632][created] = 131232342
[6742][name] = paul
[6742][created] = 131232312
[6321][name] = peter
[6321][created] = 131232311

to to

[0] = 6321
[1] = 6742
[2] = 5632

在购买力平价中达到这一目的的最快途径是什么?

Answer 1

function sort_by_date($a, $b)
{
  if ($a[ created ] == $b[ created ]) return 0;
  return ($a[ created ] < $b[ created ]) ? -1 : 1;
}

$array = array(...);
uasort($array, "sort_by_date");
$ids = array_keys($array);

http://ca.php.net/manual/en/Function.uasort.php>rel=“nofollow noreferer”>uasort 让我们使用一种习俗功能,同时保持钥匙:array_keys。

Answer 2

为什么在你只想ids的时候,努力分清所有阵列?

$times = array();
foreach ($array as $key => $item) {
    $times[$key] = $item[ created ];
}
asort($times);
$ids = array_keys($times);

Answer 3

$new_array = krsort(array_keys($your_array));

友情链接