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C2440: 类型:不能转换成:_Vector_iterator<_Ty,_Alloc>
原标题:error C2440: type cast : cannot convert from std::_Vector_iterator<_Ty,_Alloc> to DWORD
  • 时间:2010-08-24 16:17:50
  •  标签:
  • c++

我有以下错误:

error C2440:  type cast  : cannot convert from  std::_Vector_iterator<_Ty,_Alloc>  to  DWORD 
        with
        [
            _Ty=LPCSTR ,
            _Alloc=std::allocator<LPCSTR >
        ]
        No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called

采用视频演播室,2005年。 这一工作涉及的是较老的视觉演播室,但不是在现场。 这部法律造成了错误:

std::vector<LPCSTR> factions;

...

*(DWORD*)(offset+0x571) = (DWORD)factions.begin(); <- error here

我如何解决这一问题?

问题回答

您的目标是否只是消除错误或使方案正确? 在后一种情况下,你必须告诉我们,你实际上正在努力做些什么。

既然你 did,我就不得不猜测。 我的猜测是,你想要改变第1条<代码”的地址。 缩略语 如果您的法典在以前的版本中发挥作用,情况就更有可能发生。 如果我能尝试:

*(DWORD*)(offset+0x571) = (DWORD)(&factions.front());

*(DWORD*)(offset+0x571) = (DWORD)(&*factions.begin());

*(DWORD*)(offset+0x571) = (DWORD)(&factions[0]);

如果您希望转换<代码>。 缩略语 DWORD 为此:

*(DWORD*)(offset+0x571) = (DWORD)factions.front();

*(DWORD*)(offset+0x571) = (DWORD)(*factions.begin());

*(DWORD*)(offset+0x571) = (DWORD)(factions[0]);

我的意图是消除这一错误。

这完全是:*(DWORD*)(offset+0x571)=(DWORD)factions.front();





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