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• 如何把JPQL问到一个简单的 Java物体?
原标题:How to Assign a JPQL query to a simple Java object?

我需要将小 result结果分配给一个简单的小 class物体。

我有这样的想法。

class myObject() {
@id
private Long id;
private String Name;
private String description;
...
//getters and setters
}

我需要多少钱来储存这一结构的结果,例如:

// could be anytable SELECT DISTINCT c.table_id, c.name, NULL AS description FROM anyTable

我如何在JPQL中这样做,然后把结果分配给我的物体?

最佳回答

这个问题非常不明确。 因此,这是一个含糊的答复:

EntityManagerFactory emf = Persistence.createEntityManagerFactory("MyPu");
EntityManager em = emf.createEntityManager();    
Query q = em.createQuery("select f.id, f.name from Foo f");
List<Object[]> foos = (List<Object([]>)q.getResultList();

MyObject o = new MyObject();
o.setFoos(foos);
问题回答

我认为,它要回答!

SELECT NEW entities.PersonWell(c.peopleId, c.name, c.age, c.height, c.weight)
FROM 
  People AS c;

它是一个实体的构造者。 个人产品类别:

public PersonWell(Integer peopleId, String name, short age, short height, short weight, short speechspeed) {
        this.peopleId = peopleId;
        this.name = name;
        this.age = age;
        this.height = height;
        this.weight = weight;
        this.speechspeed = speechspeed;
    }

有一些成果提取法:

List<PersonWell> resultList = query.getResultList();

我希望,它会帮助你们!





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