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从8个轨道阵列中显示的植被
原标题:wxWidgets display bitmap from an 8 bit array

我有职能产生我需要抽取的阵列。 该阵列以8个轨道级图像的形式出现。 我如何适当抽取这些阵列? 我用“SretchDIBits”来拍摄图像的双双双双双双双双双双双手法,用双双双双双双双双双双双双双双手法,对这张照相。 我的问题是,我/我怎么能做一些类似的东西?

相关的工作胜利32守则


screen = LCD_image( calcs[slot].cpu.pio.lcd ) ;
        if (StretchDIBits(  hdc,
                            rc.left, rc.top, rc.right - rc.left,  rc.bottom - rc.top,
                            0, 0, lcd->width, 64,
                            screen,
                            bi,
                            DIB_RGB_COLORS,
                            SRCCOPY) == 0) {
                            printf("error in SetDIBitsToDevice
");
                        }


        if (BitBlt( hdcDest, rc.left, rc.top, rc.right - rc.left,  rc.bottom - rc.top,
            hdc, 0, 0, SRCCOPY ) == FALSE) printf("Bit blt failed
");

相关的非工作范围植被法典:

unsigned char *screen;
screen = LCD_image( calcs[gslot].cpu.pio.lcd ) ;
wxImage screenImage(rc.GetWidth(), rc.GetHeight(), screen, true);
wxBitmap bmpBuf(screenImage);
wxMemDC.SelectObject(bmpBuf);
wxDCDest->Blit(drawPoint.x, drawPoint.y, rc.GetWidth(), rc.GetHeight(), &wxMemDC, 0, 0);
wxMemDC.SelectObject(wxNullBitmap);
问题回答

wxImage ctor的预期格式是一系列的RGB数据,而您的LCD_image(<>/code>的功能并未以这种格式退回。





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