Question

I m New to bashscripting and I m seeking to go this work:

Scanning an IP range for finding devices with the port 80 open... I think it has to look like this:

#!/bin/bash
echo -----------------------------------
for ip in 192.168.0.{1,.255}; do
nmap -p80 192.168.0.1
      if #open; then
            echo "{ip} has the port 80 open"
      else
            #do nothing
fi
done
echo -----------------------------------
exit 0

我也只想看到这样的结果:

-----------------------------------
192.168.0.1 has the port 80 open
192.168.0.10 has the port 80 open
192.168.0.13 has the port 80 open
192.168.0.15 has the port 80 open
-----------------------------------

(无差错或nmap) 正常产出。

谁能帮助我这样做?

Answer 1

含有一个冰量输出参数-oG (grepable输出),使平价更为容易。同样,没有必要通过你想要扫描的所有IP地址进行修复。 nmap is Netmasknow.

你的榜样可以写成:

nmap -p80 192.168.0.0/24 -oG - | grep 80/open

<代码>-oG使可复制产出><>>>>和-具体列明了(此处为<编码>stdout)至(>)。管道符号将Nmap (stdout)的输出转向灰色,此处只有包含80/open的回归线。

Answer 2

引言

nmap --open -p80 192.168.0.*

<代码>-开放将仅列出开放港的东道方。这样,你就不必在你的手稿中检查过滤器,这已经由地图本身完成。

rel=“noretinger”>https://nmap.org/book/man-briefoptions.html

友情链接