您可以拿物体 AtIndex: from an NSSet when how You do?
I have a UIToolbar that needs three buttons in a radio style, meaning that of the three, only one button can be pushed at a time. The documentation makes reference to the possibility of setting up ...
您可以拿物体 AtIndex: from an NSSet when how You do?
有几例使用案例。 http://www.un.org/Depts/DGACM/index_chinese.htm
如果你不想要重复,不关心秩序,想要快速成员测试,则一套措施是适当的。
缩略语 AtIndex:
要求归还所有物体的NSArray的所有物体。
可使用过滤器 如果你有某种独特的识别标志来选择你所需要的物体,则要作解释。
第一,确定前提(假定你在物体上独一无二的宽度为“识别剂”,并且是一种国家动态):
NSPredicate *myPredicate = [NSPredicate predicateWithFormat:@"identifier == %@", identifier];
然后使用下列前提选择物体:
NSObject *myChosenObject = [mySet filteredSetUsingPredicate:myPredicate].anyObject;
NSArray *myArray = [myNSSet allObjects];
MyObject *object = [myArray objectAtIndex:(NSUInteger *)]
将NSUInteger改为你想要的物体索引。
用于:
//your current set
let mySet : NSSet
//targetted index
let index : Int
//get object in set at index
let object = mySet.allObjects[index]
国家抽样调查采用这一方法是为了确定物体是否在其中。
因此,例如,如果你有一个数据模型,以粗略价值界定其独特性(即财产为:
@property NSUInteger objectID;
之后,你执行就是:
- (BOOL)isEqual:(id)object
{
return (self.objectID == [object objectID]);
}
并且你可以实施洗衣:
- (NSUInteger)hash
{
return self.objectID; // to be honest, I just do what Apple tells me to here
// because I ve forgotten how Sets are implemented under the hood
}
然后,你可以拿到该身份证的物体(并检查该身份证是否在安全局内)。
MyObject *testObject = [[MyObject alloc] init];
testObject.objectID = 5; // for example.
// I presume your object has more properties which you don t need to set here
// because it s objectID that defines uniqueness (see isEqual: above)
MyObject *existingObject = [mySet member: testObject];
// now you ve either got it or existingObject is nil
但是,是摆脱国家安全局的唯一办法,是首先考虑它的独特性。
我先试了什么速度越快,但我却避免使用点数,因为这可能是线性的,而使用该成员:方法会更快。 这是更喜欢使用NSSet而不是NSArray的原因之一。
for (id currentElement in mySet)
{
// ** some actions with currentElement
}
大部分时间,你不注意从一组物体中找到一个特定物体。 你们关心检测,看看一包含有物体。 这套东西是好的。 当你想看到某一物体是否属于集邮组时,其速度要快于阵列。
如果你不关心-anyObject
,这只是给你一个物体,例如把你的手放在一个袋子里,gra取一些东西。
Dog *aDog = [dogs anyObject]; // dogs is an NSSet of Dog objects
如果你关注什么物体,则使用<代码>---------------------------------------------------------------------------------- 你需要把目标摆在你面前。
Dog *spot = [Dog dogWithName:@"Spot"];
// ...
Dog *aDog = [dogs member:spot]; // Returns the same object as above
在这里,你可以在X条码中操作一些密码,以了解更多的情况。
NSString *one = @"One";
NSString *two = @"Two";
NSString *three = @"Three";
NSSet *set = [NSSet setWithObjects:one, two, three, nil];
// Can t use Objective-C literals to create a set.
// Incompatible pointer types initializing NSSet * with an expression of type NSArray *
// NSSet *set = @[one, two, three];
NSLog(@"Set: %@", set);
// Prints looking just like an array but is actually not in any order
//Set: {(
// One,
// Two,
// Three
// )}
// Get a random object
NSString *random = [set anyObject];
NSLog(@"Random: %@", random); // Random: One
// Iterate through objects. Again, although it prints in order, the order is a lie
for (NSString *aString in set) {
NSLog(@"A String: %@", aString);
}
// Get an array from the set
NSArray *array = [set allObjects];
NSLog(@"Array: %@", array);
// Check for an object
if ([set containsObject:two]) {
NSLog(@"Set contains two");
}
// Check whether a set contains an object and return that object if it does (nil if not)
NSString *aTwo = [set member:two];
if (aTwo) {
NSLog(@"Set contains: %@", aTwo);
}
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