Question

编写以xml格式返回表数据的servlet的简单方法-？

数据来自数据库表。

Answer 1

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class TableServlet extends HttpServlet
{
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
    {
        response.setContentType("application/xml");
        PrintWriter writer = response.getWriter();
        writer.println("<?xml version="1.0"?>");
        writer.println("<table>");
        writer.println("<style>");
        writer.println("<finish>polished</finish>");
        writer.println("<material>oak</material>");
        writer.println("</style>");
        writer.println("<legs>4</legs>");
        writer.println("</table>");
        writer.flush();
    }
}

Answer 2

您可以找到jersey非常有用，它适用于XML，也支持JSONhttp://www.vogella.de/articles/REST/article.html“rel=”nofollow“>教程（参见第4节）。

友情链接