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XML 放任错误:不知情
原标题:XML Parsing Error: not well-formed

当我试图打开一页,上面的错误正在出现。 实际使用以下代码:

protected void Page_Load(object sender, EventArgs e)
{
    Response.ContentType = "text/xml";
    Response.Write(GenerateTagCloud());
    Response.End();       
}

private string GenerateTagCloud()
{
    SPWeb myweb = null;
    SPSecurity.RunWithElevatedPrivileges(delegate()
    {
        SPSite mysite1 = new SPSite(mysite.ID);
        myweb = mysite1.OpenWeb();
    });

    myweb.AllowUnsafeUpdates = true;

    SPList categories = myweb.Lists["Discussion Categories"];
    SPList discussion = myweb.Lists["Team Discussion"];

    System.Text.StringBuilder sp = new System.Text.StringBuilder();
    //System.Xml.XmlDocument doc = new System.Xml.XmlDocument();

    sp.Append("<?xml version= 1.0  encoding= UTF-8 ?>");
    sp.Append("<tags>");

    foreach (SPListItem category in categories.Items)
    {            
        string categoryname = category.Name;
        categoryname = categoryname.Replace(" ", "%20");
        sp.Append("<a href= " + myweb.Url + "/Pages/Home.aspx?Discussion=" + categoryname + "  style= font-size: 13.5pt   color= 0x7b7b7b >" + category.Name + "</a>");
    }
    sp.Append("</tags>");

    myweb.AllowUnsafeUpdates = false;
    return sp.ToString();

}

但它在产出中显示:标签的开端和 closing子的关闭;以及 如何纠正这种情况?

最佳回答

由于问题有<代码>和印本;有一类名字,你们都需要这样做——在XML中有五个特征需要逃脱:

  • & - &amp;
  • < - &lt;
    • &gt;
  • " - &quot;
  • - &apos;

<代码>&,简单改为&amp;

她说,如果是XML的书写,你应当使用<条码>XmlWriter,而不是<条码>StringBuilder——这样就能够正确逃脱,不会出现这种错误:

XmlWriter writer = XmlWriter.Create(Console.Out);
writer.WriteStartElement("Foo");
writer.WriteAttributeString("Bar", "Some & value");
writer.WriteElementString("Nested", "data & data");
writer.WriteEndElement();

取自here

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