Question

我想在现有字典中添加一个具有相应价值的钥匙。

我能够为词汇中的现有钥匙设定价值,但我无法增加新的关键价值。

希望得到任何帮助。

Answer 1

使用NSMutableDtionary

NSMutableDictionary *yourMutableDictionary = [NSMutableDictionary alloc] init];
[yourMutableDictionary setObject:@"Value" forKey:@"your key"];

www.un.org/Depts/DGACM/index_spanish.htm

下面是上述法典的迅速复制件。

var yourMutableDictionary = NSMutableDictionary()
yourMutableDictionary.setObject("Value", forKey: "Key")

但是,我建议你迅速采取审慎态度。

var yourMutableDictionary = [String: AnyObject]() //Open close bracket represents initialization

//The reason for AnyObject is a dictionary s value can be String or
//Array or Dictionary so it is generically written as AnyObject

yourMutableDictionary["Key"] = "Value"

Answer 2

NSMutableDictionary *dict = [[NSMutableDictionary alloc]init];

通过采用这一方法,我们可以给国家统计研究院增加新的价值。

[dict setObject:@"Value" forKey:@"Key"];

了解 wheat中的关键

[[dict allKeys] containsObject:@"key"];

Answer 3

从现在起,我从小子里以字典的形式获得内容,从那边,我把内容添加到其他一些字典中。

  //here contract is my json dictionary 
  NSArray *projectDBList =[contract allKeys];//listing all the keys in dict 

  NSMutableDictionary *projectsList=[[NSMutableDictionary alloc]init];

  [projectDBList enumerateObjectsUsingBlock:^(NSString * obj, NSUInteger idx, BOOL *stop) {

  [projectsList setObject:[contract objectForKey:obj] forKey:obj];

  }];

Answer 4

NSDictionnary is immutable. 可用性而是理论。

rel=“nofollow noreferer”>adding 物体:Object:forKey:

如果关键因素存在的话,测试:

[[aDict allKeys] containsObject:@"key"];

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