请允许我说,如果有条件的话,我就有一个障碍。 我怎么能够制定一种方法,使用这些同样条件,但回报真实或虚假,而不是放弃例外。 也就是说,如果一个例外被推翻,就会退回不实;如果一个例外情况被推翻,则真实返回。 我想尽可能重复使用该守则。
我也想设法避免仅仅追捕我所 throw的所有例外。
编辑:
将该守则转化为一种回收细菌的功能,然后改变原来的功能,使之称作新功能,并在返回<代码>false时作出例外规定。
共同法是否接受代表,如果出现坏情况,将予以援引(可能是一种冒犯的职能)。 然后:
if (SomethingBadHappened)
return ReportSomethingBad(new ImNotFeelingWellException("I m not feeling too well..."));
例行公文的“TryDoingSomething”版本(应当归还Fales,而不是放弃一个例外)应当与代表一起援引共同版本,但只是假冒。 “DoSomethingAndThrowExceptionIfItFails”版本应当与代表一起援引共同的例行做法,该代表将放弃已经通过的例外情况。
采用这种方式,就可以使例外情形包含比简单地产生于退回虚假的TryDoingSomething(TryDoingSomething)的更有用的信息。
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